Calculate time between received bytes

[Desdewit]

How do you calculate the time you have between received bytes to execute other commands when a pic is running with 19.606 MHz crystal and a baud rate of 9600?

[Benj]

Hello,

A 8-bit PIC runs at 1/4th of the clock frequency so at 19.6608MHz the chip is running at 4.9152MHz.

4.9152MHz / (9600 / 10) = 20480 instructions between byte receptions.

I divided the baud rate by 10 because each 8-bit byte requires a start bit and a stop bit, eg 960 bytes per second @ 9600 baud.

[Desdewit]

Hi Ben

Thanks for the reply.

4.9152MHz / (9600 / 10) = 20480 instructions between byte receptions.

19660800 /960 = 20480