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When two inductors are connected in series, the same current flows in each of them and the effective inductance of the circuit will always be greater than any one of the two inductors taken alone. The effective inductance of a circuit with two inductors (L1 and L2) connected in series is simply the sum of the two inductance values. Thus the effective inductance, L, of the circuit will be given by:
L = L1 + L2
Similarly, where three inductors (L1, L2, and L3) are connected in series, the effective inductance of the combined circuit will be given by:
L = L1 + L2 + L3
<^< Inductor Construction | Course index | Inductors in Parallel >^>
